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It is dangerous to be sincere, unless you are also stupid! |
he beams are the arteries of the system, in a manner of speaking. They have a rectangular crossection and are hollow. Their interior floors are used as roadbeds for the propulsion vehicles that are travelling inside the beams. One could use 2 or 3 sizes of beams for carrying the traffic, depending on the size of the largest and heaviest cars that are supposed to travel on them. Or rather, since, in general, most beams are meant to carry varying sizes of beamcars, the beams will have to be sized according to the weight of the heaviest load that each beam segment will be subjected to.We realize, of course, that there are as many solutions to beam design and function as there are imaginative inventors. This webpage reflect the thoughts of us at SwedeTrack, but it certainly is not the "Gospel according to SwedeTrack". We have had many fruitful discussions with other developers. |
This is a rather technical page. We will deal with:
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The special considerations pertaining to the FLYWAY® system are also dealt with on a separate page. |
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he dimensions on the first 2 lines for the so-called b-beam agrees with those of SIPEM's in Dortmund, Germany. The SIPEM-beam is dimensioned for 11-ton-cars, and since the SwedeTrack cars will be much lighter, this would allow for more than 1 car between the poles at any one moment. In a big network, it is reasonable to expect tempory queues of cars at rare intervals.One can always use other criteria to dimension the beams, but it is more convenient, considering the standardized width of propulsion cars, to only vary the height of the beams to accomodate various loads. |
![]() Figure 1:1 |
To be reasonably compatible with FLYWAY®, the beams should contain:
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Suitable construction materials
he debate about the best material to be used in beams and supports is still going on. This is excerpts from Eunitrans-discussions. The main criterias are, of course:
Pressed aluminum might be an alternative in the future due partly to the capital intensity in production. Aluminum beams of the same strength as steel are slightly more expensive than welded steel beams, but this is compensated for the first time one does not have to maintain the guideway. And there is no downtime for maintenance, which is critical in transport hubs. The manufacture of pressed or "extruded" alumuminium saves a lot of labor compared with welded steel. An alu beam will weigh half of a steel beam with the same strength, but alu is 3 times costlier as material. Thus, one ends up with some 10-20 % more costly alu beams. But they are much cheaper regarding maintenance, so the end long term result is that alu would be cheaper. Experts on materials at the Norwegian Technical University in Trondheim recommend that far more attention should be spent into using more expensive materials like composites in the vehicles, since some 85 % of the weight carried by the beams would on average be due to the weight of the vehicles and not the people inside. On the other hand, when reflecting over the arguments that labour counts, not raw materials - then that argument diminishes a bit, though it still remains as important for energy usage.
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Since steel is dead cheap, the cost of more steel is not the problem per se. However, weight as such is a problem since foundations must be more solid. Transport also would be more costly. But again you have the maintenance factor and in the very long run, aluminum wins. However, "in the long run we all are dead" meaning you have to sell the product first, and caring how long something will last has a limit for the buyer, when he considers the far more immediate investment cost.
It is difficult to say in general what is cheapest when all factors are taken into consideration. "It all depends" as usual. Zinced steel doesn't need any maintenance. Welding of guideway sections must be automated. One can buy ready sections of guideway in countries where labor cost is low. Motorcars are often zinced, and that does not stop them from rusting. It only postpones the problem, like an efficient paint. Steel eventually rusts and have a costly downtime period during maintenance. One has to evaluate the cost of automated welded and zinced steel against extruded aluminum. It seems that the winner in the long run would be aluminum, or possibly magnesium, but a buyer may have a shorter time-horizon and that gives steel an opening.
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The stiffness to weight ratio of steel, aluminium, magnesium and concrete is about the same, so to achieve a particular limit of bending with the same external cross section, you will need more of the lighter materials in inverse proportion to their weight. I think concrete will win in terms of stiffness per US $.
Aluminium has just over twice the thermal expansion of steel and concrete, meaning that more expansion joints will needed. |
s stated in the listing above, a beam network which is to be scalable and complex needs at least 3 kinds of electronic sensors inside the beams. They would communicate with passing propulsion cars and exchange relevant information. This would serve 3 different purposes: |
![]() Figure 2:1 |
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The other illustration above (figure 2:2) gives an idea how a beamcarīs positioning above a berth would be facilitated with the aid of a sensor. The sensors transmit carrier waves in the microwave-range. These would both serve to transmit data and function as radar. The range is very short, about 10-15 yards, as these waves are quickly attenuated as a function of the square of the distance from the transmitter. When a car approaches, it will be detected by this radar, and the sensor would identify itself and send a "who-are-you?" request. The car would identify itself. This identification of the car is not necessary if this is a sensor above a berth, but if it is the first kind of sensor among those listed above, this beamcar-identity would be relayed to the local node. However, the car has 2 transponders, one at each end of the propulsion car. As the car nears the sensor, those transponders will register a gradually stronger signal from the sensor. As the car slowly passes the sensor, the fore transponder will register a weaker signal, while the aft transponder will still register increasing signal strength. When both transponders get the same signal strength from the sensor, the car is in the right position.
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Figure 2:2
Techniques for deciding the position of moving objects is coming into use more and more. The best-known system is the GPS, which is short for Global Positioning System. It has been created by the US Military and consists of 26 satellites that orbit the Earth in such a way that they are reasonably evenly distributed at any single moment. If the GPS-receiver can receive the signal from at least 3 of these satellites, it can use a mathematical technique known as triangulation to determine its position on Earth. Each satellite transmits its location, i.e. longitude and latitude for the place it happens to be above at the moment. The receiver detects the angles between the three signals, and the rest is mathematics. Aircrafts, detecting the signals from 4 satellites, can also use these signals to determine their altitudes. Vertical measurements can also be incredibly exact; in November 1999, the correct altitude of Mount Everest was put to 8850 meters above sea level, 2 meters higher than previously determined. (This does not necessarily mean that previous measurements were less exact, though. The Himalayas are still rising.) The US Military have introduced disturbances to the signals that makes it hard to determine the position of an object with any better precision than 100 meters. For that reason, EU has decided to introduce its own positioning system, called Galileo. This should be available by the year 2008. In the meantime, the GPS-system is complemented by a groundbased system called DGPS, which enhance the precision by very nearly compensate for the built-in error. In this system, the base stations help the mobile unit to decide which satellites to tune in to, instead of the mobile unit having to check all available satellite signals and decide for itself which signals are the strongest. This saves time and power for the mobile unit. The established GPS-system is not usable for positioning beam-vehicles, mainly because:
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It can rather easily be calculated how the dimensions and the thickness of a hollow, rectangular profile influences its ability to withstand sideways strain. Using Wy as a symbol for the profileīs ability to withstand vertical bending, and the proportional measurements from the figure at right, we get: The amount of material required for the profile is of course proportional to its dimensions and its thickness. Using M for the amount of material per unit length, we get: |
One can thus see that increasing H-h at the expense of B-b leads to the most vertical-bending-resistant beam for a given beam-mass.
In other words, for a given mass per unit length, the H/B ratio of the beam should be as large as practicable. Intuitively, one realizes that this applies to the |
![]() Figure 3:1 |
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e naturally want the beams to be as light and slim as possible, while still performing their function satisfactorily. We can identify five factors that are relevant for this aim:
The primary factor limiting the beamīs dimensions is not that it will break but that it will bend. When a beam is loaded down by its own weight and the weight of passing vehicles it will in fact hang down somewhat, like a clothesline hanging between two trees. In the case of the beam, you should not be able to see this downbending - but it is there. And it will be felt by the travellers, unless some cushioning is built into the beamcars. This bending of the beams causes the vehicle to go up and down during travel, like in a ski lift. At high speeds, this makes the ride uncomfortable for passengers. The faster you go, the worse it will feel, and therefore the straighter the beam must stay, as the beamcars pass by. How much the beam will bend under load depends on how elastic the beam material is, and that elasticity is inversely proportional to the E-module of the material in the beam. When a vertical force Fy is applied to a horizantal beam with cross-sectional area A and lenght l, the downhang in the middle between the supports is where E is a material-dependent constant called the elasticity module, or E-module for short. Steel has an E-module of 200 GN/m2, whereas unallyoed aluminum is weaker with 70 GN/m2. Thus, steel is more suitable than aluminum from this point of view, as it is almost 3 times as strong. Plastic has an E-module which is about one tenth of steel. Arming the plastic with fibers will however significantly increase the E-module.
![]() Figure 4:1.
(N = Newton; we assume here an even load distrbution along the beam segment) Another important factor is the geometric resistance to bending of the beam. Assuming that:
(i.e. (H - h)/2) and |
![]() Figure 4:2Ix = the sum of all dA * y2if S is much smaller than H, then Ix = 2 * S * B (H/2)2
A rectangular beam which is 1 meter high and 1 meter broad made of 2 cm. thick steel will have a resistance for bending of about 1* 0.02 * 1/2 or 0.01 m4. If you choose to make the beam 0.5 m high and 2 m broad from the same material, it would have a resistance to bending of about 2* 0.02* 0.25/2 = 0.0025 cm4 or one fourth of the beam in the first example. Both beams would weigh the same per meter length. Clearly, it is essential to make the beamsī vertical dimension as big as practícable.
When a beam is erected between two vertical supports and uniformly loaded, it will flex down between these supports with a vertical distance of As an example, let us assume a load of 20 tons or 200 kN (= kiloNewton; Newton is kilos * 9.81 at sea level, or roughly 10) and that the distance between the two beam supports is 30 meters. Assume Ix = 0.02 m4 and that the E-module is 200 GN/m2. At the middle between the two supports the beam would then flex down:
Figure 4:3
At a low velocity this will clearly not be felt at all. Even when travelling at 30 m/s or 108 km/h the up-down acceleration will be 0.014 m2/s which is neglible compared to the gravitational constant 9.81 m/s2. We could thus make a weaker beam in this case.
This is a very simplified way to look at the problem, though. When taking vibrations, wind induced loads etc into account the picture gets much more complex. However, the basic facts remain, for instance that a high beam is stronger (relative to the amount of material used) than a broad one. ![]() Figure 4:4In order to set a standard, it might be best to adopt the present interior measures of the Sipem beam in Dortmund (about 1.1 m high and 0.8 m wide). Or, in order to standardize production, one could use the dimensions of 0.8 * 0.8 meters for the smallest vehicles. As heavier vehicles and/or longer spans are required, extra heights could be successively added as reinforcements, as shown in figure 4:4 above. In conjunction with adding these reinforcements, the polesī upper parts could be raised correspondingly by adding prefabricated vertical extensions to them, above the beams. Using this method, the bottom of the beam would have to be strong enough from the beginning to handle the heaviest vehicles, as indicated by R in figure 4:4. |
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hose readers that are familiar with mechanics realize that there will be en extra, momentary downward strain upon the beams when the lowered cabins have to be elevated from the ground up to the beams to continue their journey. As shown in figure 5:2, the weight of the car when it leaves the ground (orange arrow) is transferred to the beam (yellow arrow) as a downward pull. In addition to this, there is an extra downward strain on the beam, proportional to the acceleration of this lifting process. One can see in the illustration the advantage of putting a support at precisely this place (as in B) rather than far away from a beam support (as in A).The acceleration component of this strain is, however, not as big as one might think. The downward pull (F) is proportional to the applied upward acceleration of the car, according to the formula
where m is the mass of the cabin (including its load) and a is the acceleration. As an example, let us assume that: |
![]() Figure 5:2
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where x is the lifting height (in meters) and t is the time (in seconds). Using our figures, we get:
which makes a = 1.25 m/s2. In the first formula, F = m*a, a is normally put to 9.81 m/s2 for an object at rest. This is the Earthīs acceleration at sea level. So, comparing "our" acceleration to that of the Earth, we get 1.25/9.81 = 0.127. This means that lifting the cabin from the ground up to underneath the beam using these figures, will add about 12 - 13 % of the cabins weight to the strain that the beam must carry. This added strain is rather marginal. The beam segments are only joined at the poles, and thus cannot all have standardized lengths. There are 2 ways of joining beams that are most common:
(B in figure 5:1). |
etīs hang a string of boiled spaghetti on 2 supports, as shown in Figure 6:1. If itīs cooked "al dente" it should have some stiffness left (every cook knows that spaghetti should not be boiled too long!). Using the x-y coordinate system, we can discribe the curvature of the spaghetti asy = f(x). At points B1 the spaghetti is level, while at points B2 it has the steepest slopes. These slopes can be mathematically expressed as the rate at which the value of y changes as a function of x, or dy/dx = f '(x). As can be readily realized, the tendency for the spaghetti to bend is largest at points B1, where Why is that? Because at those points the rate of change in the sloping is at its biggest. From d2y/dx2 = f ''(x). Clearly, if we could find a place where this tendency to bend is zero, or It would be an ideal point to join two beam segments together. This point would not then be subjected to any bending stress, only the force of pull, which would be easier to handle. These points are found at B2 in the figure, and, when it comes to steel beams, these points are about 1/6 of the distance from one support to the next. These points are called inflexion points. When considering the beams, these inflexion points must not be stiff; the beam segments must be able to move. This is motivated by the fact that the beams will expand and contract in response to variations in temperature, at least if they are made of metal, such as steel beams.
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![]() Figure 6:1![]() Figure 6:2![]() Figure 6:3
Another reason for these inflexion points is that the beams could be prefabricated with an upward bent (grossly exaggerated in figure 6:3 to compensate for the downward stress of passing beamcars. When the cars pass, the beam will bend down and its ends will need space to move outwards, somewhat (indicated by the blue arrows). |
o doubt you have noticed ribs on the beams on our drawings. They resemble cooling flanges, but intuitively you have probably felt that they serve the same stabilizing purpose as the ribs in old-time wooden sailing vessels. But why are they needed here?Consider the downbending force that each beam section is subjected to by
This bending movement will spread upwards along the sides of the beam as shown by F2, until the roof will either tend to sink or buckle down in the middle (shown by F3), depending on which force wins out. To prevent this, one could of course make the sidewalls thicker. But if you look at the mathematics further up on this page, you will realize that thicker walls do not contribute much to the stiffness of the beam. This extra material is better spent in forming ribs at regular intervals along the beams, to counteract this outflaying force. They will need to cover the roof as well as the sides of the beam, resembling an inverted "U". They will have to cover the bottom of the beam as well, meeting up with the slit. Now, these ribs could either be applied externally or internally on the beam, as indicated by the brown coloring in the drawing. Internal ribs have two advantages:
Another consideration would be to decide upon the distance (D) between the ribs, and the thickness (T) of the ribs. Calculations show that D should be somewhere around 120 cm and T about 5 cm. |
![]() Figure 7:1![]() Figure 7:2 |
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Lines drawn from their meeting point (at "x") towards the beam at any point on the bent section will have the same length, no matter at what angle they are drawn. That distance (r in the figure) from "x" to the center of the beam is termed "bending radius". In the case of turning round street corners, berthing at stations and the like, we will have to consider a radius of about 6 meters. In all other cases, this radius will be much larger. |
![]() Figure 8:1. |
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ake a look at figure 6:3 above once again! It illustrates the upwards pre-bending (or "camber") at the time of manufacture, to compensate for gravityīs impact on the beam. This camber could be made a bit more than what is required for the dead load alone (i.e. the weight of passing beamcars and of the beam segment itself). The live-load vertical deflection caused by the moving car, with a maximum at center-span (i.e. equi-distant between the beam supports), can be added to the dead load camber, so that the unloaded beam support would bend slightly upwards.Otherwise, the beamcar, on passing each beam segment, would create a hammock-effect. This means that it would travel slightly downhill to the middle of the beam segment, then be faced with a small hill to climb, which will flatten out as the car reaches the center of the support. The downhang would of course, in such a case, spring back up when the load is gone. These vertical movements of the beam as the beamcar pass will hardly be noticeble by the eye, but they might be felt by the traveler at high speeds, unless the pre-cambering is done right. |
Essentially, the travelers might experience a yoyo-effect which is more emphasized the faster the car travels. On the other hand, the downward bend gets smaller, the faster the car travels. This is because of the beamīs inertia; it takes time for the beam to react to the weight of the beamcar. The quicker the car passes the beam segment, the smaller vertical distance the beam will travel in response to the carīs weight, before the car is gone. This can be seen from the table at right, where the required camber for different speeds has been calculated. One realizes intuitively, then, that one should avoid:
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Continuous beam deflects into a sine curve
a = vertical acceleration, m/sec^2 then: a = 2 * p2 * d/L * v2/L
a is a function of the beam material and proportional design, and is a measurement as to how quickly the beam segment would respond to an applied weight. For a given a, one gets the vertical deflection d from:
One can thus see that the beamīs vertical deflection is proportional to the square of the length of the beam segment (which is natural) but inversely proportional to the square of the speed of the passing cars. Maximum vertical deflection (in meters) if a = 0.2
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| Copyright Đ 2004, SwedeTrack System. | Last Updated: 2007-01-17 |
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