Calculating Curved Beams
 Figure 1:3
Look at figure 1:3. Two straight beam elements, L1 and L2, are joined with a curved element, with radius of curvature = r. We will assume level beams, and forget about the Z-coordinate in this illustration. The points where the beams join, x1y1 and x2y2 respectively, could both be on the curving part of the curved beam, or one or both of them could be on a straight part of the curved beam segment. In the figure, we have chosen to let point x2y2 be a bit away from the circle that designates the curvature. How would we calculate then?
Extending the straight beams from points x1y1 and x2y2, we find that those extensions come together at point P. These extensions can be regarded as y being a funcion of x. Since they are straight, they have constant slopes, k1 and k2. We designate these slopes as:
k1 = y/x and k2 = y/x. Then;
| For L1: | y = k1*x + y1 |
| For L2: | y = k2*x + y2 |
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At point xp, ypthe lines cross each other. Thus:
y on L1 = y on L2 = yp
and: k1*xp + y1 = k2*xp + y2
==> k1*xp = k2*xp + y2 - y1
==> (k1 - k2)*xp = y2 - y1
And we arrive at the coordinates of point P:
xp = (y2 - y1)/(k1 - k2)
yp = k1*Xp + y1.
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Let us define the bisector that goes through the center of the circle and through point P:
kb is thus the slope of the bisector, and we find that:
y - yp = kb(x - xp).
We will then define the point P3 as having the coordinates x3 and y3.
We can now designate the endpoint coordinates of the radius r on the perifery as S1 and S3. Then:
The bisector will then have the slope k3.
The equation for the radius r to point P3 could then be expressed as:
kr = -1/k3
y - y3 = kr*(x- x3)
In this manner, we have found a way to convert between the circular coordinates of curved beams and the "straight" coordinates of the XY-system. Sloping beams can then be treated in a similar manner, and be mapped onto the XYZ-coordinate system. Sloping beams are in themselves straight, but the junctures between horizontal and sloping beams can be regarded as vertical curves. The most complicated features to map onto a coordinate system would be those beams that bend horizontally and vertically at the same time. But these formulas make it posible to tackle those situations as well. |